intermediate algebra review of ch. 1-6 pg. 449

review ch. 1-6. pg 449

solve each equation:

1. 3x-2=5

3x-2+2=2+5

3x=7

x=7/3

the solution to the equation is 7/3.

2. 3/5x =-2

3/5x.5/3=-2.5/3

x=10/3

in a fraction a person can think of it as a division; multiply, invert, to both sides of the equation.

3. 2(x-2)=4x

this is a multiplication

2x-4=4x

2x-2x-4=4x-2

-4=2x factored and lcd with 2 in both -4 and 2.

2/-4=-2=2x/2

-2=x

4. 2(x-2)=2x

2x-4=2x
2x-2x-4=0

-4=0

5. 2(x+3)=6x+6

2x+6=6x+6

2x=6x

2x-2x=2x-6x

0=4x

0=x

6. 2(3x+4)+x2=0

6x+8+x2=0

combine like terms

x2+6x+8=0

factor out the terms

(x+2)(x+4)=0

muldtiply x2.8=8x2 4+2=6 4.2=8

X=-2 or x=-4.

x+2=0 x+4=0.

Marie Zajac BA in psychology with a concentration in rehabitation counseling.