Saturday, February 20, 2010

ch.7 ex. 7.1 exercise 13 algebra

question #13. pg. 459

13. y=2x+4
3x+y=-1

y=2x+4 is already in the y slope inter cept form
is a line with a slope of 2 and a y intercept of (0,4)

3x+y=1 is not in the y slope form.

or y=-1 or y=-3x-1 is a line with a slope of -3 and y intercept of (0,-1)
put y= on one side the left side of the equation, subtract 3 from both sides; placing the 3 from one side of the equal sign to the right side the 3 brcomes-3. The slope becomes -3, the intercept begins at 0,and 1 becomes(0,-1).

The lines on the graph intersect at (-1,2), the solution set then is (-1,2).

ex. pg. 216

3x+2y=8
2y=-3x+8
y=-3/2x+4 slope intercept form.

15. pg. 459

y=-1/2x+4 x+2y=8
this is in y intercept slope form.
this is the same as the first equation. All points on the line satisfies both equations. The solution set is (x,y) (x+2y=8)

that is all for now
Marie Zajac
Bachelor of Arts deggree in Psychology with a concentration in rehabilitation in Counseling.

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